Four particles \(P,Q,R\) and \(S\) of masses \(m,m,m\) and \(2m\) respectively are kept at the four corners of a square of side \(\sqrt{2}\,\text{m}\). The distance of the centre of mass of the system of particles from the particle \(S\) is
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For particles,
\[
\boxed{
x_{CM}=\frac{\sum m_ix_i}{\sum m_i},
\qquad
y_{CM}=\frac{\sum m_iy_i}{\sum m_i}.
}
\]
Choose the heaviest particle as the origin whenever it simplifies the calculations.