Question:medium

Four particles \(P,Q,R\) and \(S\) of masses \(m,m,m\) and \(2m\) respectively are kept at the four corners of a square of side \(\sqrt{2}\,\text{m}\). The distance of the centre of mass of the system of particles from the particle \(S\) is

Show Hint

For particles, \[ \boxed{ x_{CM}=\frac{\sum m_ix_i}{\sum m_i}, \qquad y_{CM}=\frac{\sum m_iy_i}{\sum m_i}. } \] Choose the heaviest particle as the origin whenever it simplifies the calculations.
Updated On: Jul 18, 2026
  • \(1.2\,\text{m}\)
  • \(0.8\,\text{m}\)
  • \(0.6\,\text{m}\)
  • \(0.4\,\text{m}\)
Show Solution

The Correct Option is B

Solution and Explanation

Was this answer helpful?
0