Question

Four elements from the second period Boron to Oxygen can have the following IE$_1$ values (in kJ mol$^{-1}$): 1086.5, 800.6, 1313.9, 1402.3. The value of IE$_1$ for Nitrogen is:

• A. 1086.5
• B. 800.6
• C. 1402.3
• D. 1313.9

Hint:

In ionization energy trends, the half-filled p-orbitals of Nitrogen make it more stable, requiring more energy to remove an electron.

Answer 1

The Correct Option is C

Concept: Lenz's Law states that the induced current will flow in a direction to oppose the change in magnetic flux that produced it. Step 1: Analyze \(L_1\) interaction. \(L_1\) has a current (let's say producing flux \(\Phi_1\)). If \(L_1\) moves **towards** \(L_2\), the flux through \(L_2\) increases. \(L_2\) must induce a current to repel \(L_1\) (oppose the increase). If \(L_1\) current direction (anticlockwise) creates a North pole towards right, \(L_2\) needs a North pole towards left (Anticlockwise). Wait, we need Clockwise. Let's assume standard interaction: If \(L_1\) (Anticlockwise) moves Towards \(L_2\), \(L_2\) induces opposing current (Clockwise). So, **Move \(L_1\) Towards \(L_2\)**.
Step 2: Analyze \(L_3\) interaction. \(L_3\) (Clockwise) moves relative to \(L_2\). If \(L_3\) moves **Away** from \(L_2\), the flux from \(L_3\) through \(L_2\) decreases. \(L_2\) must induce a current to attract/sustain the flux. Since \(L_3\) is Clockwise, \(L_2\) will induce Clockwise current to maintain the field. So, **Move \(L_3\) Away from \(L_2\)**. Conclusion: Moving \(L_1\) towards and \(L_3\) away both contribute to inducing a clockwise current in \(L_2\). \[ \boxed{\text{Correct option is (1)}} \]