Question:medium
For \( |x| < 1 \), the constant term in the expansion of \( \frac{1}{(x-1)^{2}(x-2)} \) is
For \( |x| < 1 \), the constant term in the expansion of \( \frac{1}{(x-1)^{2}(x-2)} \) is
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To find the constant term, set $x=0$ in the expression.
Updated On: Apr 10, 2026
- 2
- 1
- 0
- $-\frac{1}{2}$
Show Solution
The Correct Option is D
Solution and Explanation
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