Question:medium

For the reaction find energy released ²₁H + ²₁H → ⁴₂He BE/A for \(^2_1H = 1.1 \, \text{MeV}\) and for \(^4_2He = 7.2 \, \text{MeV}\):

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The energy released in nuclear reactions can be calculated by finding the difference between the binding energies of the reactants and the products. The energy per nucleon can be found by dividing the energy released by the number of nucleons.

Updated On: Apr 7, 2026

24.4 MeV
6.2 MeV
6.1 MeV
8 MeV

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The Correct Option is A

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For the reaction find energy released ²₁H + ²₁H → ⁴₂He BE/A for \(^2_1H = 1.1 \, \text{MeV}\) and for \(^4_2He = 7.2 \, \text{MeV}\):

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The Correct Option is A

Solution and Explanation

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