Question:medium

For the given arrangement of charges, find the strength of electric field \( E \) and potential \( V \) at the geometrical center \( O \).

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In symmetrical charge distributions, the electric field at the center cancels out, but the electric potential remains non-zero.
Updated On: Jan 29, 2026
  • \( E = 0; V = 0 \)
  • \( E = 0; V = \text{Non-zero} \)
  • \( E = \text{Non-zero}; V = \text{Non-zero} \)
  • \( E = \text{Non-zero}; V = 0 \)
Show Solution

The Correct Option is B

Solution and Explanation

To solve this problem, we need to analyze both the electric field \( E \) and the electric potential \( V \) at the center \( O \) of the given arrangement of charges.

  1. The image shows a symmetric arrangement of charges on a pentagon, with each vertex having a charge \( q \).
  2. Electric Field \( E \):
    • The electric field due to a point charge at any other point is given by the formula: E = \frac{kq}{r^2}, where \( k \) is Coulomb's constant, \( q \) is the charge, and \( r \) is the distance from the charge.
    • Due to symmetry, the resultant electric field at the geometric center \( O \) will be zero because the individual electric field vectors from all the charges will cancel out each other.
    • Therefore, \( E = 0 \).
  3. Electric Potential \( V \):
    • The electric potential due to a point charge is given by: V = \frac{kq}{r}.
    • Electric potentials are scalar quantities and can be added algebraically.
    • The potential at \( O \) due to each charge is equal and additive because they do not cancel each other as vectors do.
    • Thus, the net potential \( V \) at the center will be non-zero.
  4. Conclusion:
    • For the given charges, the electric field \( E \) at the center is zero while the electric potential \( V \) is non-zero.
    • The correct option is: E = 0; V = \text{Non-zero}.
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