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For the curve $(\frac{x}{a})^n + (\frac{y}{b})^n = 2$, ($n \in N$ & $n>1$) the line $\frac{x}{a}+\frac{y}{b}=2$ is

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To prove that a line is tangent to a curve at a specific point, you must show two things: (1) the point lies on both the line and the curve, and (2) the slope of the line is equal to the derivative of the curve's function evaluated at that point.

Updated On: Mar 30, 2026

a normal for all values of n
a normal for only values of n more than Max\{a,b\}
a tangent for all values of n
a tangent for only values of n more than Min\{a,b\}

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The Correct Option is C

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For the curve $(\frac{x}{a})^n + (\frac{y}{b})^n = 2$, ($n \in N$ & $n>1$) the line $\frac{x}{a}+\frac{y}{b}=2$ is

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The Correct Option is C

Solution and Explanation

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