Question:medium

Following are the four molecules ``P``, ``Q``, ``R`` and ``S``. Which one among the four molecules will react with H-Br(aq) at the fastest rate? Molecules:

\[ P: \text{Cyclic compound with two O groups attached to the ring.} \] \[ Q: \text{Cyclic compound with one O group and one CH\(_3\) group attached to the ring.} \] \[ R: \text{Cyclic compound with one O group attached to the ring and one CH\(_3\) group attached to the ring.} \] \[ S: \text{Cyclic compound with one CH\(_3\) group attached to the ring.} \]

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The speed of reaction with H-Br is influenced by the electron-donating or electron-withdrawing groups attached to the molecule. Electron-donating groups stabilize the carbocation intermediate, leading to faster reactions.
Updated On: Jan 14, 2026
  • S
  • Q
  • R
  • P
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The Correct Option is B

Solution and Explanation

The objective is to identify the cyclic compound exhibiting the highest reaction rate with aqueous H-Br. An analysis of each option is provided:

  1. Molecule P:
    • This molecule features two oxygen atoms bonded to a ring structure.
    • While the oxygen atoms can contribute to resonance stabilization, their electron-withdrawing nature decreases ring electron density, diminishing reactivity towards nucleophilic attack by H-Br.
  2. Molecule Q:
    • This molecule comprises a ring substituted with one oxygen atom and one methyl (CH\(_3\)) group.
    • The oxygen atom enhances reactivity through electron donation via resonance, and the methyl group offers inductive stabilization.
    • This combined effect significantly increases the ring's reactivity towards H-Br, leading to a faster reaction.
  3. Molecule R:
    • Similar to molecule Q, this molecule contains an oxygen atom and a methyl group attached to the ring, but their arrangement differs.
    • The specific positional isomerism and resonance effects, when compared to Q, suggest a less favorable reaction due to steric and electronic considerations.
  4. Molecule S:
    • This molecule consists of a benzene ring with two methyl (CH\(_3\)) groups.
    • The absence of an oxygen atom renders it the least reactive among the presented options when exposed to H-Br.

Based on this assessment, molecule Q is predicted to react most rapidly with H-Br(aq). This is attributed to the electron-donating capacity of the oxygen atom facilitating the reaction, and the stabilizing influence of the methyl group via hyperconjugation on the transition state.

Correct Answer: Q

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