Following are the four molecules ``P``, ``Q``, ``R`` and ``S``. Which one among the four molecules will react with H-Br(aq) at the fastest rate? Molecules:

\[ P: \text{Cyclic compound with two O groups attached to the ring.} \] \[ Q: \text{Cyclic compound with one O group and one CH\(_3\) group attached to the ring.} \] \[ R: \text{Cyclic compound with one O group attached to the ring and one CH\(_3\) group attached to the ring.} \] \[ S: \text{Cyclic compound with one CH\(_3\) group attached to the ring.} \]
The objective is to identify the cyclic compound exhibiting the highest reaction rate with aqueous H-Br. An analysis of each option is provided:
Based on this assessment, molecule Q is predicted to react most rapidly with H-Br(aq). This is attributed to the electron-donating capacity of the oxygen atom facilitating the reaction, and the stabilizing influence of the methyl group via hyperconjugation on the transition state.
Correct Answer: Q
In the reaction: P + Q longrightarrow ?R + S The time taken for 75% reaction of P is twice the time taken for 50% reaction of P. The concentration of Q varies with time as shown in the figure. The overall order of the reaction is: 