Question:medium

Find the value of  $\log_{20} 100 + \log_{20} 1000 + \log_{20} 10000 \quad \bigl[\textit{Assume that } \log 2 = 0.3\bigr].$ 
 

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For $\log_a b$ with common logs, use $\log_a b=\frac{\log b}{\log a}$. Precompute $\log a$ once.
Updated On: Jul 16, 2026
  • $90/13$
  • $80/13$
  • $110/13$
  • $70/13$ 

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The Correct Option is A

Solution and Explanation

Step 1: Find \( \log20 \) via \( 20=4\times5 \): \[ \log20=\log4+\log5=2\log2+(1-\log2)=1+\log2=1+0.3=1.3. \]

Step 2: Each term converts as \( \log_{20}10^k=\dfrac{k}{1.3} \), so the sum is \[ \frac{2+3+4}{1.3}=\frac{9}{1.3}. \]
\[ \boxed{\frac{90}{13}} \]
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