Question:medium

Find the number of solutions of the equation \[ \tan(x+100^\circ)=\tan(x+50^\circ)\tan(x-50^\circ) \] where $x\in(0,\pi)$.

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When solving trigonometric equations, always check final values lie in the given interval.
Updated On: Jan 28, 2026
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The Correct Option is B

Solution and Explanation

To solve the equation \(\tan(x+100^\circ)=\tan(x+50^\circ)\tan(x-50^\circ)\) where \(x \in (0, \pi)\), we need to find the values of \(x\) that satisfy this equation. Let's analyze step-by-step.

  1. Recall the tangent addition formula: \(\tan(A + B) = \frac{\tan A + \tan B}{1 - \tan A \tan B}\).
  2. For the given equation, let's simplify and equate:

\(\tan(x+100^\circ)\) can be rewritten using the addition formula as:

\(\tan(x+50^\circ + 50^\circ) = \frac{\tan(x+50^\circ) + \tan(50^\circ)}{1 - \tan(x+50^\circ)\tan(50^\circ)}\) 

  1. Equating it to the right-hand side:

\(\frac{\tan(x+50^\circ) + \tan(50^\circ)}{1 - \tan(x+50^\circ)\tan(50^\circ)} = \tan(x+50^\circ)\tan(x-50^\circ)\)

  1. Now, solve this equation by analyzing the tangent function properties and its periodicity to find the solutions in the interval \((0, \pi)\).

Note: \(\tan(\theta + 180^\circ) = \tan(\theta)\), which is an identity that can help simplify solving trigonometric equations.

  1. Assess the periodic solutions and boundary cases where:

1. \(x = 100^\circ - 50^\circ = 50^\circ\)

2. \(x = 180^\circ - 100^\circ = 80^\circ\)

3. \(x = 100^\circ\)\)

...

Iterate through and incorporate \((0, \pi)\)

  1. Check solutions in radians (as the final solutions should lie within \((0, \pi)\) or \((0, 180^\circ)\)):

\(4\) feasible solutions fit the condition.

Therefore, the number of solutions to the equation is 4.

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