Question:medium

Find the distance of point $P(3, 4)$ from the origin.

Show Hint

Distance from origin formula: \[ \sqrt{x^2 + y^2} \] Recognize Pythagorean triples like $(3,4,5)$ to solve quickly.
Updated On: Feb 26, 2026
Show Solution

Solution and Explanation

Step 1: Understanding the Question:
The question asks for the distance between a given point P(3, 4) and the origin (0, 0) on a 2D Cartesian plane.
Step 2: Key Formula or Approach:
The distance \(D\) of a point \((x, y)\) from the origin \((0, 0)\) is calculated using a simplified version of the distance formula, which is derived from the Pythagoras theorem:
\[ D = \sqrt{x^2 + y^2} \] Step 3: Detailed Explanation:
The coordinates of the given point P are \((x, y) = (3, 4)\).
This means we have \(x = 3\) and \(y = 4\).
Substitute these values into the distance from origin formula:
\[ D = \sqrt{(3)^2 + (4)^2} \] Next, calculate the squares of the numbers:
\[ D = \sqrt{9 + 16} \] Add the values inside the square root:
\[ D = \sqrt{25} \] Finally, compute the square root:
\[ D = 5 \] Step 4: Final Answer:
The distance of the point P(3, 4) from the origin is 5 units.
\[ \boxed{5} \]
Was this answer helpful?
0