Question

Find moment of inertia about axis shown which is equidistant from both spheres

Answer 1

Correct Answer: 88500

To find the moment of inertia (I) of the system about the axis shown, which is equidistant from both spheres, follow these steps:

\(I=[\frac{2}{5}Mr^{2}+M(0.2)^{2}]\times 2\)

\(=[\frac{2}{5}\times 2\times (0.1)^{2}+2\times (0.2)^{2}]\times 2\)

\(=[\frac{4}{500}+\frac{8}{100}]\times 2\)

\(=\frac{44\times 2}{500}=\frac{88}{500}(kg-m^{2})\)

So, the correct answer is \(\frac{88}{500} (kg-m^{2})\)