The given reaction involves the elimination of HCl from the starting compound in the presence of NaOH, leading to the formation of an alkene as the major product 'P'. Let's identify the number of π electrons in 'P'.
Step 1: Identify Elimination The reaction mechanism is likely E2, resulting in the removal of H from the β-carbon adjacent to the chlorine-bearing carbon, forming a double bond.
Step 2: Draw the Product 'P' Convert the starting structure into the expected alkene. The structure of 'P' will have a double bond.
Step 3: Count π Electrons in Product 'P' An alkene (C=C) contains 2 π electrons in its double bond.
Thus, the number of π electrons in 'P' is 2.
Verification: The computed number of π electrons (2) fits within the provided range (2, 2).
