Question:medium

Equation of tangent to the circle \(x^2 + y^2 - 2x - 2y + 1 = 0\) perpendicular to \(y = x\) is given by

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For tangent: use distance from center = radius.

Updated On: Apr 16, 2026

\(x + y + 1 = 0\)
\(x + y = 2 + \sqrt{3}\)
\(x - y + 3 = 0\)
\(x - y + 1 = 0\)

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The Correct Option is B

Solution and Explanation

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Equation of tangent to the circle \(x^2 + y^2 - 2x - 2y + 1 = 0\) perpendicular to \(y = x\) is given by

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The Correct Option is B

Solution and Explanation

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