Question:medium

Elimination of arbitrary constants $A$ and $B$ from $y = Ae^x + Be^{-2x}$ gives the differential equation:

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Exponential solutions directly give roots of characteristic equation.
Updated On: Apr 24, 2026
  • $\frac{d^2y}{dx^2} + \frac{dy}{dx} - 2y = 0$
  • $\frac{d^2y}{dx^2} + \frac{dy}{dx} + 2y = 0$
  • $\frac{d^2y}{dx^2} - \frac{dy}{dx} - 2y = 0$
  • $\frac{d^2y}{dx^2} - 2\frac{dy}{dx} + y = 0$
  • $\frac{d^2y}{dx^2} + 2\frac{dy}{dx} + y = 0$
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The Correct Option is A

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