The de Broglie wavelength of a particle is inversely proportional to its momen tum (p = mv), and it helps describe wave-particle duality
To evaluate the truthfulness of the statements provided about the cathode rays, we will analyze each statement one by one:
(A) The deBroglie wavelength of the electron emitted is \(66667 \, \text{nm}\):
The deBroglie wavelength \(\lambda\) is calculated using the formula \(\lambda = \frac{h}{mv}\), where \(h\) is Planck's constant, \(m\) is mass of the electron, and \(v\) is its velocity.
Given: \(h = 6 \times 10^{-34} \, \text{Js}\), \(m = 9 \times 10^{-31} \, \text{kg}\), \(v = 1000 \, \text{m/s}\).
Plugging in these values, \(\lambda = \frac{6 \times 10^{-34}}{9 \times 10^{-31} \times 1000}\).
Calculating, \(\lambda = \frac{6 \times 10^{-34}}{9 \times 10^{-28}}\).
\(\lambda = \frac{2}{3} \times 10^{-6} \, \text{m} = \frac{2}{3} \times 10^{3} \, \text{nm} = 0.667 \, \text{nm}\).
Therefore, statement (A) is false.
(B) The characteristic of electrons emitted depend upon the material of the electrodes of the cathode ray tube:
This statement is true. The material of electrodes influences the characteristics such as work function which affects the emission of electrons.
(C) The cathode rays start from cathode and move towards anode:
This is correct and describes the basic principle of cathode ray tubes. Thus, statement (C) is true.
(D) The nature of the emitted electrons depends on the nature of the gas present in cathode ray tube:
This statement is false. The electrons in cathode rays are not influenced by the gas present; they are inherent to the materials and structure of the tube.
In conclusion, the true statements are (B) and (C), tallying to a total of 2. The computed value 2 falls within the expected range [2,2].
Considering Bohr’s atomic model for hydrogen atom :
(A) the energy of H atom in ground state is same as energy of He+ ion in its first excited state.
(B) the energy of H atom in ground state is same as that for Li++ ion in its second excited state.
(C) the energy of H atom in its ground state is same as that of He+ ion for its ground state.
(D) the energy of He+ ion in its first excited state is same as that for Li++ ion in its ground state.