Question:medium

Eight identical spherical liquid drops, each falling with a terminal velocity $v$, coalesce to form a single large drop. The terminal velocity of the new large drop is:

Show Hint

When identical drops combine: \[ R = n^{1/3} r \] and since terminal velocity follows: \[ v \propto r^2 \] therefore: \[ v' = n^{2/3} v \]
Updated On: May 16, 2026
  • $2v$
  • $4v$
  • $8v$
  • $16v$
Show Solution

The Correct Option is B

Solution and Explanation

Was this answer helpful?
0