Question:medium

During thermodynamic process, the increase in internal energy of a system is equal to the work done on the system. Which process does the system undergo?

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In an adiabatic compression, work done on the gas increases its temperature and internal energy.
Updated On: May 16, 2026
  • Isothermal
  • Adiabatic
  • Isochoric
  • Isobaric
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Question:
We use the First Law of Thermodynamics to relate heat, work, and internal energy for various processes.
Step 2: Key Formula or Approach:
First Law of Thermodynamics: $Q = \Delta U + W_{by}$, where $W_{by}$ is work done BY the system.
Equivalently, $Q = \Delta U - W_{on}$, where $W_{on}$ is work done ON the system.
Step 3: Detailed Explanation:
Given: $\Delta U = W_{on}$.
Substituting this into the first law:
\[ Q = \Delta U - \Delta U = 0 \]
A process in which there is no heat exchange ($Q = 0$) between the system and its surroundings is called an Adiabatic process.
In such a process, all work done on the system is stored as internal energy.
Step 4: Final Answer:
The system undergoes an adiabatic process.
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