Question:medium
During a chemical reaction \( X \rightarrow Y \), the rates of reaction starting with initial concentrations of \( X \) as \( 4.0 \times 10^{-3} M \) and \( 2.0 \times 10^{-3} M \) are \( 4.8 \times 10^{-4} \, mol \, L^{-1}/s \) and \( 1.2 \times 10^{-4} \, mol \, L^{-1}/s \) respectively. What is the order of reaction with respect to \( X \)?
During a chemical reaction \( X \rightarrow Y \), the rates of reaction starting with initial concentrations of \( X \) as \( 4.0 \times 10^{-3} M \) and \( 2.0 \times 10^{-3} M \) are \( 4.8 \times 10^{-4} \, mol \, L^{-1}/s \) and \( 1.2 \times 10^{-4} \, mol \, L^{-1}/s \) respectively. What is the order of reaction with respect to \( X \)?
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To find order, compare rate ratios with concentration ratios using \( \frac{r_1}{r_2} = \left(\frac{[A]_1}{[A]_2}\right)^n \).
Updated On: May 6, 2026
- 2
- 3
- 1.5
- 1
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The Correct Option is A
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