Question

Directions: The following table shows the percentage population of six states (A to F) that lives below the poverty line, along with the male to female ratio among the population below the poverty line and above the poverty line, for each state.

State	% Population below poverty line	Below Poverty line M:F	Above Poverty line M:F
A	16	2:3	3:4
B	10	4:3	5:2
C	14	3:4	2:3
D	20	5:2	4:3
E	25	4:1	2:1
F	20	2:3	4:1

If the total population of state A is 5000, then what is the number of females above the poverty line in state A?

• A. 2000
• B. 2400
• C. 2600
• D. data inadequate

Hint:

First find 84% of 5000 for the population above poverty line, then split it using the 3:4 male to female ratio.

Answer 1

The Correct Option is B

Step 1: Work with direct percentages instead of a fraction of population.
State A: 16% below the poverty line means 84% above it. The ratio $3:4$ for males to females above the poverty line means females are $\frac{4}{3+4} = \frac{4}{7}$ of that 84% share, which is about $\frac{4}{7} \times 84\% = 48\%$ of the total population of A.

Step 2: Apply this percentage to the total population.
Total population of A is 5000. So females above the poverty line make up 48% of 5000, roughly $48\% \times 5000 = 2400$ (using the exact fraction $\frac{48}{100} = \frac{4}{7} \times 0.84$ gives the same clean value).

Step 3: Cross check using the male side.
Males above the poverty line are $\frac{3}{7}$ of 84%, which is 36% of 5000, so $0.36 \times 5000 = 1800$. Adding both groups, $2400 + 1800 = 4200 = 84\%$ of 5000, so the answer is consistent.

Final Answer:
Females above the poverty line in state A equal 2400. \[ \boxed{2400} \]