Question

Correct statement is : (A) $\text{NaOCl}$ when reacted with $\text{KI}$ gives $\text{KOI}$ (B) $\text{KOI}$ is best reducing agent (C) Methanoic acid gives iodoform test (D) Isopropyl alcohol gives iodoform test (E) $\text{H}_3\text{C}–\text{CH}=\text{CH}–\text{CO}–\text{CH}_3$ gives iodoform test

• A. A, B, C only
• B. B, D only
• C. D, E only
• D. B, C, D only

Hint:

The iodoform test only requires the presence of $\text{R}-\text{CO}-\text{CH}_3$ or $\text{R}-\text{CH}(\text{OH})-\text{CH}_3$. Unsaturation far from the reactive center (E) does not interfere with the test mechanism.

Answer 1

The Correct Option is C

To solve the problem, we need to evaluate each of the statements and options given: 

1. Statement (A): \(\text{NaOCl}\) when reacted with \(\text{KI}\) gives \(\text{KOI}\).
   • Sodium hypochlorite (\(\text{NaOCl}\)) and potassium iodide (\(\text{KI}\)) actually react to produce iodine, not potassium hypoiodite (\(\text{KOI}\)). Therefore, statement (A) is incorrect.
2. Statement (B): \(\text{KOI}\) is the best reducing agent.
   • Potassium hypoiodite (\(\text{KOI}\)) is not commonly considered the most effective reducing agent. Other compounds are much more recognized for this property. Therefore, statement (B) is incorrect.
3. Statement (C): Methanoic acid gives an iodoform test.
   • The iodoform test is given by compounds containing a methyl ketone group (\(\text{CH}_3\text{CO}-\)) or related alcohols, after their oxidation. Methanoic acid does not contain a methyl ketone group and thus does not give the iodoform test. Therefore, statement (C) is incorrect.
4. Statement (D): Isopropyl alcohol gives the iodoform test.
   • Isopropyl alcohol (\(\text{CH}_3\text{CH(OH)CH}_3\)) can be oxidized to a methyl ketone, which reacts positively in the iodoform test Producing a yellow precipitate of iodoform. Therefore, statement (D) is correct.
5. Statement (E): \(\text{H}_3\text{C}–\text{CH}=\text{CH}–\text{CO}–\text{CH}_3\) gives the iodoform test.
   • This compound contains a methyl ketone group, allowing it to undergo the iodoform reaction, which makes statement (E) correct.

After evaluating each statement, the correct options that hold true are D and E only. Therefore, the correct answer is

D, E only

.