Question

Consider two coils in which a current in one coil carrying \(6\) A causes the change in the flux in the second coil \(12\times 10^{-4}\) weber/turn. The second coil has \(2000\) turns. The mutual inductance between the coils is

• A. \(0.2\) H
• B. \(0.3\) H
• C. \(0.4\) H
• D. \(2.4\) H

Hint:

Mutual inductance is N times the flux per turn divided by the current.

Answer 1

The Correct Option is C

Step 1: Total Flux Linkage:
Total flux linked with coil 2 $=2000\times12\times10^{-4}=2.4$ Wb-turns.

Step 2: Divide by Current:
$M=\dfrac{2.4}6=0.4$ H.

Step 3: Answer:
Option (C).

Final Answer:
Option (C). \[ \boxed{\text{(C) } 0.4\ \text{H}} \]