Question:medium

Consider the two redox reactions I and II \[ \text{I. }2\mathrm{Na_2S_2O_3}+ \mathrm{I_2} \rightarrow \mathrm{Na_2S_4O_6}+2\mathrm{NaI} \] \[ \text{II. }2\mathrm{KMnO_4}+10\mathrm{FeSO_4}+3\mathrm{H_2SO_4} \rightarrow 2\mathrm{MnSO_4}+5\mathrm{Fe_2(SO_4)_3}+2\mathrm{K_2SO_4}+3\mathrm{H_2O} \] The ratio of equivalent weights of \(\mathrm{KMnO_4}\) and \(\mathrm{Na_2S_2O_3}\) is \[ (\mathrm{K}=39u;\ \mathrm{Mn}=55u;\ \mathrm{O}=16u;\ \mathrm{Na}=23u;\ \mathrm{S}=32u) \]

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Equivalent weight is given by \[ \boxed{ \text{Equivalent weight} = \frac{\text{Molar mass}}{\text{n-factor}}. } \] For acidic \(\mathrm{KMnO_4}\), \(n=5\), while for \(\mathrm{Na_2S_2O_3}\), \(n=1\).
Updated On: Jul 18, 2026
  • \(1:1\)
  • \(2:1\)
  • \(1:5\)
  • \(5:1\)
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The Correct Option is C

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