
For the provided reaction coordinate diagram:
- \( E_1 \) denotes the activation energy of the forward reaction.
- \( E_2 \) denotes the activation energy of the reverse reaction.
- The total energy for the forward reaction is \( E_1 + E_2 \). The product exhibits greater stability than the reactant, evidenced by its lower position on the energy scale relative to the reactant.
Therefore, option (4) is the correct choice.
Consider the given figure and choose the correct option:
Consider the following graph between Rate Constant (K) and \( \frac{1}{T} \): Based on the graph, determine the correct order of activation energies \( E_{a1}, E_{a2}, \) and \( E_{a3} \).

For reaction \(A \rightarrow P\), rate constant \(k = 1.5 \times 10^3\ s^{-1}\) at \(27^\circ C\). If activation energy for the above reaction is \(60\ kJ\ mol^{-1}\), then the temperature (in \(^{\circ}C\)) at which rate constant \(k = 4.5 \times 10^3\ s^{-1}\) is ______. (Nearest integer) \[ \text{Given: } \log 2 = 0.30,\ \log 3 = 0.48,\ R = 8.3\ J\ K^{-1}\ mol^{-1},\ \ln 10 = 2.3 \]