To solve this question, we need to understand the reaction mechanism involved.
The reaction starts with the compound CH\(_3\)NH\(_2\) reacting with PhCOCl in the presence of pyridine (Py). This step is an acylation reaction where the amino group attacks the acyl chloride, resulting in the formation of an amide.
The intermediate compound X formed here is likely an amide, specifically PhCH\(_2\)NHCOPh.
The next step involves the reduction of this amide using LiAlH\(_4\), a strong reducing agent. LiAlH\(_4\) can reduce amides to amines by removing the carbonyl group (C=O).
Reduction of the amide PhCH\(_2\)NHCOPh leads to the formation of an amine, specifically toluene (PhCH\(_3\)).
Thus, the product Y is toluene (PhCH\(_3\)).
Let's analyze the provided options:
Option 1: PhCH\(_2\)NHCOPh - This is the intermediate amide but not the final product.
Option 2: Ph–CH\(_2\)NCH\(_2\)Ph - This structure does not match the reduction product in similar reactions.
Option 3: PhNH\(_2\)CH\(_2\)Ph - This structure is incorrect as LiAlH\(_4\) would typically not lead to such a rearrangement.
Option 4: PhCH\(_3\) - This is the correct final product after reduction.
Therefore, the correct structure of Y is PhCH\(_3\) (toluene).
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