Consider the following organic reaction sequence. Choose the final product (X) from the following (consider the major product in all intermediate reactions).
Step 1: Understanding the Question:
The question asks for the final product of a multi-step synthesis starting from an organic acid. Based on the options and standard JEE reactions, let's analyze the sequence. Note: The starting material image likely represents Benzoic Acid. Step 2: Detailed Explanation:
1. Step (i) (\(C_{6}H_{5}COOH \xrightarrow{NH_{3}/\Delta}\)): Acid reacts with ammonia and heating results in dehydration to form an amide. Product: Benzamide (\(C_{6}H_{5}CONH_{2}\)).
2. Step (ii) (\(C_{6}H_{5}CONH_{2} \xrightarrow{Br_{2}/NaOH}\)): This is the Hoffmann Bromamide Degradation. The amide loses the carbonyl group to form a primary amine with one less carbon. Product: Aniline (\(C_{6}H_{5}NH_{2}\)). This is the intermediate (X) mentioned.
3. Step (iii) (\(C_{6}H_{5}NH_{2} \xrightarrow{HNO_{2}, 0^{\circ}C}\)): Diazotization reaction. Aniline reacts with nitrous acid at low temperature to form a stable diazonium salt. Product: Benzenediazonium chloride (\(C_{6}H_{5}N_{2}^{+}Cl^{-}\)).
4. Step (iv): The reaction mentions \(C_{6}H_{5}N_{2}Cl\) as a reagent and \(H_{2}O, 0^{\circ}C\). Usually, if diazonium is heated with water, it gives phenol. If it undergoes coupling with phenol, it gives an azo dye.
Looking at the sequence: Starting acid \(\rightarrow\) amide \(\rightarrow\) amine \(\rightarrow\) diazonium \(\rightarrow\) phenol. Phenol is a standard option. Step 3: Final Answer:
The sequence results in the formation of Phenol.
