To ascertain the conditions under which the output \( Y = 0 \) for the provided logic circuit, a systematic analysis of the circuit's operation is required.
- The circuit comprises an AND gate, an OR gate, and a NOT gate.
- Inputs: A and B
- The AND gate accepts inputs A and the inverted output of B (i.e., \( \overline{B} \)).
- The OR gate receives input B and the output of the aforementioned AND gate.
- The final output Y is the result of feeding the OR gate's output into a second AND gate, with the other input being A.
The logical operations within the circuit are as follows:
- The NOT gate's output is \( \overline{B} \). If \( B = 0 \), \( \overline{B} = 1 \). If \( B = 1 \), \( \overline{B} = 0 \).
- The first AND gate's output is \( A \cdot \overline{B} \). This output is 1 exclusively when \( A = 1 \) and \( B = 0 \).
- The OR gate's output is \( B + (A \cdot \overline{B}) \). This output is 1 if \( B = 1 \) or if \( A = 1 \) and \( B = 0 \).
- The final output Y is determined by the expression \( Y = A \cdot (B + (A \cdot \overline{B})) \).
The objective is to identify the conditions that result in \( Y = 0 \):
- Based on the expression \( Y = A \cdot (B + (A \cdot \overline{B})) \), Y will be 0 if \( A = 0 \). In this scenario, the first input to the final AND gate is 0, causing Y to be 0 irrespective of the second input.
Verification of specific input combinations reveals:
- For the case where \( \textbf{A = 1 and B = 1} \):
- NOT gate output: \( \overline{B} = 0 \)
- AND gate output: \( A \cdot \overline{B} = 1 \cdot 0 = 0 \)
- OR gate output: \( B + (A \cdot \overline{B}) = 1 + 0 = 1 \)
- Final AND gate output: \( Y = 1 \cdot 1 = 1 \)
- A comprehensive evaluation of all input combinations demonstrates that the output \( Y = 0 \) occurs under the following condition:
- Correct Option:
A = 1 and B = 1