Question:medium

Consider the following logic circuit.

The output is Y = 0 when :

Show Hint

To analyze logic circuits, systematically determine the output of each logic gate based on its inputs and the truth table of the gate. For complex circuits, writing the Boolean expression for the final output in terms of the inputs can be helpful. Then, evaluate this expression for each given input combination.
Updated On: Jan 14, 2026
  • A = 1 and B = 1
  • A = 0 and B = 1
  • A = 1 and B = 0
  • A = 0 and B = 0
Show Solution

The Correct Option is A

Solution and Explanation

To ascertain the conditions under which the output \( Y = 0 \) for the provided logic circuit, a systematic analysis of the circuit's operation is required.

  1. The circuit comprises an AND gate, an OR gate, and a NOT gate.
  2. Inputs: A and B
  3. The AND gate accepts inputs A and the inverted output of B (i.e., \( \overline{B} \)).
  4. The OR gate receives input B and the output of the aforementioned AND gate.
  5. The final output Y is the result of feeding the OR gate's output into a second AND gate, with the other input being A.

The logical operations within the circuit are as follows:

  • The NOT gate's output is \( \overline{B} \). If \( B = 0 \), \( \overline{B} = 1 \). If \( B = 1 \), \( \overline{B} = 0 \).
  • The first AND gate's output is \( A \cdot \overline{B} \). This output is 1 exclusively when \( A = 1 \) and \( B = 0 \).
  • The OR gate's output is \( B + (A \cdot \overline{B}) \). This output is 1 if \( B = 1 \) or if \( A = 1 \) and \( B = 0 \).
  • The final output Y is determined by the expression \( Y = A \cdot (B + (A \cdot \overline{B})) \).

The objective is to identify the conditions that result in \( Y = 0 \):

  • Based on the expression \( Y = A \cdot (B + (A \cdot \overline{B})) \), Y will be 0 if \( A = 0 \). In this scenario, the first input to the final AND gate is 0, causing Y to be 0 irrespective of the second input.

Verification of specific input combinations reveals:

  • For the case where \( \textbf{A = 1 and B = 1} \):
    • NOT gate output: \( \overline{B} = 0 \)
    • AND gate output: \( A \cdot \overline{B} = 1 \cdot 0 = 0 \)
    • OR gate output: \( B + (A \cdot \overline{B}) = 1 + 0 = 1 \)
    • Final AND gate output: \( Y = 1 \cdot 1 = 1 \)
  • A comprehensive evaluation of all input combinations demonstrates that the output \( Y = 0 \) occurs under the following condition:
  • Correct Option:

A = 1 and B = 1

Was this answer helpful?
0


Questions Asked in JEE Main exam