Question

What best can be concluded about the number of players coached by Zara?

• A. Exactly 3
• B. Exactly 2
• C. Either 2 or 3
• D. Either 2 or 3 or 4
• A. Player-1, Player-3, Player-4, Player-8
• B. Player-1, Player-3, Player-4
• C. Player-1, Player-3, Player-4, Player-6
• D. Player-1, Player-4, Player-6, Player-8

Answer 1

The Correct Option is B

1. Yuki trained only even-numbered players: 2, 4, 6, and 8, for a total of 4 players.

2. Xena trained more players than Yuki. Since Yuki trained 4 players, Xena trained at least 5.

3. Zara trained only odd-numbered players: 1, 3, 5, and 7.

4. Let's count the players trained by each coach:

• Yuki trained 4 players (2, 4, 6, 8).
• Xena trained more than Yuki, meaning Xena trained at least 5 players.
• Zara trained exactly 2 players: Player 1 and Player 4. This is because Player 1 and Player 4 were trained by the same coach.

5. Zara trained exactly 2 players. Therefore, the correct answer is:
Answer: Option 1: Exactly 2

Answer 2

Here are the given conditions regarding player ratings and coach assignments:
• Yuki coaches Players 2, 4, 6, and 8.
• Zara coaches Players 1, 3, 5, and 7.Nbsp;
• Xena coaches all other players.

Following these conditions and noting that Player 5 and Player 7 have the same rating, we determine the following ratings:
• Player 2: 7
• Player 4: 6
• Player 6: 4
• Player 8: 3
• Player 1: 2
• Player 3: 5
• Player 5: 7
• Player 7: 4

Therefore, Player 7's rating is 4.

Answer 3

Coaches and Players:

• Yuki: Players 2, 6, 8.Nbsp;
• Zara: Players 3, 5, 7.
• Xena: Players 1, 4.

Key Constraints:

• Total rating sum = 32.
• Player 2 has the highest rating of 7.
• Players 5 and 7 have the same rating, denoted by z.
• Player 4's rating is double Player 8's rating (x), so Player 4 = 2x.
• All ratings are unique, except for Players 5 and 7.
• Yuki's average rating is twice Xena's average rating, and 2 more than Zara's average rating.

Assign Ratings:

• x = 2 (Player 8), so Player 4 = 2x = 4.
• z = 6 (Players 5 and 7).
• Player 3 = 3, Player 1 = 5.
• Player 6 = 5.

Therefore, Player 6's rating is 5.

Answer 4

1	Yuki	Ratings for even-numbered players are averages.
2	7	Even-numbered, with the highest individual ratings.
3	Xena	Ratings vary among individuals.
4	Yuki	Together with Player-1.
5	Zara	Same as Player-7.
6	3	Average calculation.
7	Zara	Included in the group.
8	1	Tied to Player-4's rating.

The given conditions allow coaches to interpret their teams differently, helping to identify players with certainty by cross-referencing these conditions. For instance, Player-2 has the highest rating, Player-1 and Player-4 are considered together, and Yuki is associated with more coaches. Player ratings should be planned based on the average condition, balanced with the highest mark and Player-8's relation to Player-4.

Player-5 and Player-7 received the same rating. Considering different combinations helps to better understand scores using the average of 4. By reviewing the conclusions in reverse, players are correctly aligned, with Player-2, Player-4, and Player-8 being rated as appropriately capable.

Players Rated	Conclusion
1,2,4,5,7,8	6 players received perfect scores.

A total of 6 players were rated correctly, falling within the [6,6] range. This aligns with the conditions and scores highest based on meaning.

Answer 5

Xena, Yuki, and Zara are coaches. We need to determine which players Xena trained based on given conditions.

1. Yuki trains only even-numbered players (2, 4, 6, 8). Zara trains only odd-numbered players (1, 3, 5, 7).

2. Xena must therefore train a mix of odd and even players.

3. Rule 1: Yuki trained Player-2. Since Player-2 has the highest rating among even players and Yuki trains all even players, it's logical for Yuki to train Player-2. Yuki must also train another even-numbered player (either 6 or 8). However, Xena must train more players than Yuki.

4. Rule 3: Zara trained Player-5 and Player-7. These players received the same rating. They are both trained by Zara and evaluated, as their ratings do not overlap with other coaches, except in this specific instance.

5. Given the above constraints, Xena trains the remaining players: Player-1, Player-3, Player-4, and Player-8. This is due to the averaging of ratings and the identified player overlaps.

Xena trains more players than Yuki (whose assigned players are 2 and 6, making a two-player group). Xena also trains both odd and even players. Therefore, Xena successfully trains Player-1, Player-3, Player-4, and Player-8.