Question:medium

Compound A from the following reaction sequence is 
 Br2 , C S 2 0 βˆ’ 5 Β° C 0 βˆ’ 5 Β° 𝐢 β†’ 𝐡 π‘Ÿ 2 , 𝐢 𝑆 2 B. N a N O 2 / H C l

Updated On: Apr 1, 2026
  • Benzoic acid
  • Salicylic Acid
  • Phenol
  • Aniline
Show Solution

The Correct Option is D

Solution and Explanation

The given reaction sequence involves the conversion of a compound into Aniline. Let’s examine the steps involved in the sequence:

  1. The first step involves bromination using \(Br_2\) in carbon disulfide (\(CS_2\)) at a temperature of 0–5Β°C. This typically adds bromine atoms to the compound. Given the presence of benzene, it leads to the formation of bromo-derivative compounds.
  2. In the second step, sodium nitrite (\(NaNO_2\)) and hydrochloric acid (\(HCl\)) are used to convert the bromo compound to a diazonium salt via the formation of nitrous acid. The reaction with nitrous acid is typical for the diazotization of aromatic amines.
  3. Finally, the diazonium salt is reduced using hypophosphorous acid (\(H_3PO_2\)) to form aniline, an aromatic amine.

Thus, the sequence of reactions results in the formation of Aniline from an aromatic compound through bromination, diazotization, and reduction.

Option analysis:

  • Benzoic acid: This compound is not typically produced from the given reaction sequence without carboxylation steps.
  • Salicylic Acid: Typically formed by Kolbe-Schmitt reaction; not applicable here.
  • Phenol: Phenol can be produced from diazonium salt but not in this specific sequence and conditions.
  • Aniline: Correct answer as per the given reaction mechanism explained above.

Conclusion: The correct answer is Aniline.

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