Question:medium

Compare the relative stability of given carbocations.
\(\text{CH}_{3}\text{-}\text{C}^{+}\text{-(CH}_{3})_{2}\) (I) \(\text{CH}_{3}\text{-}\text{C}^{+}\text{H-CH}_{3}\) (II) \(\text{CH}_{3}\text{-}\text{C}^{+}\text{H}_{2}\) (III)

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More alkyl groups give more +I effect and more hyperconjugation, so stability increases.
Updated On: Nov 12, 2026
  • III > II > I
  • II > I > III
  • I > III > II
  • I > II > III
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Classify
The ions are tertiary, secondary and primary respectively.

Step 2: Rule
Stability order: $3^{\circ}>2^{\circ}>1^{\circ}$.

Step 3: Compare the options
Only option D gives I > II > III.

Final Answer:
The tertiary ion is the most stable. \[ \boxed{\text{(D) }\text{I}>\text{II}>\text{III}} \]
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