Question

Choose the correct option

Molecule		Shape
A	\(BrF_5\)	i	T-shape
B	\(H_2O\)	ii	See-saw
C	\(ClF_3\)	iii	Bent
D	\(SF_4\)	iv	Square Pyramidal

• A. (A)- IV, (B)- III, (C)- I, (D)- II
• B. (A)- III, (B)- IV, (C)- I, (D)- II
• C. (A)- II, (B)- I, (C)- III, (D)- IV
• D. (A)- I, (B)- III, (C)- IV, (D)- II

Answer 1

The Correct Option is A

VSEPR Theory Analysis of Molecules:
BrF₅: Exhibits a square pyramidal geometry due to five bonding pairs and one lone pair around bromine.
H₂O: Water's structure is bent, characterized by two bonded pairs and two lone pairs.
ClF₃: Chlorine trifluoride adopts a T-shape configuration with three bonded pairs and two lone pairs.
SF₄: Sulfur tetrafluoride displays a see-saw shape, resulting from four bonded pairs and one lone pair.

Molecule-Shape Matching:
(A) BrF₅ - Square pyramidal
(B) H₂O - Bent
(C) ClF₃ - T-shape
(D) SF₄ - See-saw

Conclusion: The corresponding shapes align with Option (1).