Question:hard
ચાર અનપેર્ડ ઇલેક્ટ્રોનવાળો લેન્થેનાઇડ આયન છે (આપેલ છે: Ce = 58, Nd = 60, Tb = 65 અને Ho = 67):
ચાર અનપેર્ડ ઇલેક્ટ્રોનવાળો લેન્થેનાઇડ આયન છે (આપેલ છે: Ce = 58, Nd = 60, Tb = 65 અને Ho = 67):
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f-ઓર્બિટલમાં 7 ઓર્બિટલ્સ હોય છે, તેથી ઇલેક્ટ્રોન ભરાતી વખતે પહેલા 7 એકલા ભરાય છે.
Updated On: Jun 23, 2026
- Ho³⁺
- Nd³⁺
- Ce³⁺
- Tb³⁺
Show Solution
The Correct Option is D
Solution and Explanation
Step 1: Electronic configuration.
Ho(67): [Xe]4f11 6s2. Ho3+: remove 2 from 6s, 1 from 4f → [Xe]4f10.
Step 2: Count unpaired.
4f10: \( \uparrow\downarrow\; \uparrow\downarrow\; \uparrow\uparrow\; \uparrow\uparrow\; \uparrow\uparrow\; \uparrow\uparrow \) = 4 unpaired.
Step 3: Final.
\[ \boxed{Ho^{3+} \text{ has 4 unpaired electrons}} \]
Ho(67): [Xe]4f11 6s2. Ho3+: remove 2 from 6s, 1 from 4f → [Xe]4f10.
Step 2: Count unpaired.
4f10: \( \uparrow\downarrow\; \uparrow\downarrow\; \uparrow\uparrow\; \uparrow\uparrow\; \uparrow\uparrow\; \uparrow\uparrow \) = 4 unpaired.
Step 3: Final.
\[ \boxed{Ho^{3+} \text{ has 4 unpaired electrons}} \]
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