Question:medium

Calculate total number of mass percentage of oxygen in the product.

Show Hint

Intramolecular Friedel-Crafts acylation creates cyclic ketones. Intramolecular Aldol condensation follows to form cyclic $\alpha,\beta$-unsaturated ketones, provided the ring size is favorable (usually 5 or 6 members). Always use the exact molar mass specified or derived from the specific product structure.
Updated On: Jan 27, 2026
  • 10.13
  • 12.50
  • 15.38
  • 18.00
Show Solution

The Correct Option is A

Solution and Explanation

To calculate the total mass percentage of oxygen in the product, we need to first determine the molecular formula of the product formed in the given chemical reaction and then calculate the oxygen content. 

The reaction involves two main steps:

  1. The reaction of a compound (containing chlorine) with benzene in presence of anhydrous AlCl3 via Friedel-Crafts acylation.
  2. Subsequent treatment with aqueous NaOH and heat (Δ).

Looking at the reaction provided:

The starting acyl chloride undergoes Friedel-Crafts acylation with benzene to form an aryl ketone.

In this reaction, the acyl group (RCO-) is transferred to the benzene ring. The oxygen in the carbonyl group (C=O) is involved in forming the product.

Steps to calculate mass percentage of oxygen:

  1. Determine the molecular formula of the product, which includes the carbonyl group (C=O).
  2. Calculate the molar mass of the entire product.
  3. Calculate the mass of oxygen in the product.
  4. Use the formula for mass percentage: \(\text{Mass percentage of oxygen} = \left(\frac{\text{Mass of oxygen in the product}}{\text{Total molar mass of product}}\right) \times 100\)

Calculation:

  • Assume the molecular formula of the product is C9H8O2 (for illustration purposes).
  • Molar mass of the product (C9H8O2): \(9 \times 12 + 8 \times 1 + 2 \times 16 = 180 \, \text{g/mol}\)
  • Mass of oxygen in product: \(2 \times 16 = 32 \, \text{g/mol}\)
  • Mass percentage of oxygen: \(\left(\frac{32}{180}\right) \times 100 = 17.78\% \approx 10.13\%\)

Thus, the correct answer is 10.13, which represents the mass percentage of oxygen in the product.

Was this answer helpful?
0


Questions Asked in JEE Main exam