The question is about determining the number of \(\pi\)-electrons in two aromatic compounds: benzene (C\(_6\)H\(_6\)) and naphthalene. Both compounds follow Hückel's rule, which states that a molecule is aromatic if it has \(4n+2\) \(\pi\)-electrons, where \(n\) is a non-negative integer.
- Benzene (C\(_6\)H\(_6\)):
- Benzene consists of a single ring with 6 carbon atoms.
- Each carbon atom contributes one \(\pi\)-electron, making a total of 6 \(\pi\)-electrons.
- Since 6 \(\pi\)-electrons fit the formula \(4n+2\) (where \(n=1\)), benzene is aromatic.
- Naphthalene:
- Naphthalene consists of two fused benzene rings.
- Each ring contributes 6 \(\pi\)-electrons, making a total of 12 for two rings. However, due to the structure of naphthalene, it actually has 10 \(\pi\)-electrons.
- 10 \(\pi\)-electrons satisfy the \(4n+2\) rule (where \(n=2\)), confirming its aromaticity.
From the explanations above, we deduce:
- Benzene has 6 \(\pi\)-electrons.
- Naphthalene has 10 \(\pi\)-electrons.
Therefore, the answer is: 6,10.