Question:medium

C = 100 pF, V = 100 V (given spherical capacitor).
Identical capacitor is touched with this capacitor. If change in total energy is α × 10^-7 J then find α = ?
(Combined capacitance = 200 pF)

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When capacitors are connected in parallel, their capacitances add. To find the change in energy, calculate the energy before and after the connection using \( E = \frac{1}{2} C V^2 \).

Updated On: Apr 7, 2026

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The Correct Option is A

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C = 100 pF, V = 100 V (given spherical capacitor). Identical capacitor is touched with this capacitor. If change in total energy is α × 10^-7 J then find α = ? (Combined capacitance = 200 pF)

Show Hint

The Correct Option is A

Solution and Explanation

Top Questions on Quantum Mechanics

Questions Asked in JEE Main exam

C = 100 pF, V = 100 V (given spherical capacitor).
Identical capacitor is touched with this capacitor. If change in total energy is α × 10^-7 J then find α = ?
(Combined capacitance = 200 pF)