Question:medium

Bond between A and B can be represented by A \(\rightarrow\) B, A\(^+\)B\(^-\), A\(^-\)B\(^+\). If A is more electronegative than B, then least contribution to the actual structure comes from

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Electronegativity determines charge distribution in polar bonds.
Updated On: Jun 16, 2026
  • I
  • II
  • III
  • All the structures have equal contribution
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The Correct Option is B

Solution and Explanation

To solve this question, we need to evaluate the different bond representations provided: A \(\rightarrow\) B, A\(^+\)B\(^-\), and A\(^-\)B\(^+\), and determine which has the least contribution to the actual molecular structure when element A is more electronegative than element B.

  1. A \(\rightarrow\) B: This structure represents a coordinate bond where electron pair is donated by A to B. Since A is more electronegative, it is plausible but not the dominant structure.
  2. A\(^+\)B\(^-\): In this ionic representation, A has a positive charge, and B has a negative charge. However, since A is more electronegative, it will not easily lose electrons to become positively charged. Hence, this structure is unrealistic and contributes the least.
  3. A\(^-\)B\(^+\): This structure implies A having a negative charge and B a positive charge. Being more electronegative, A holds on to electrons more tightly, making this structure more reasonable than II.

Considering the nature of electronegativity, the least probable structure when A is more electronegative than B is A^{+}B^{-} (II), where the more electronegative element (A) is assigned a positive charge.

Hence, the correct option is II.

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