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Beena got married 8 years ago. Today, her age is $\tfrac{11{4}$ times her age at the time of marriage. If her daughter’s age is $\tfrac{1}{10}$ times her age, then her daughter’s age is:}

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When a child’s age is given as a fixed fraction of the parent’s age “today,” set up $D=\text{fraction}\times A$ first; many questions then resolve directly from the options.
Updated On: Jul 15, 2026
  • 3 years
  • 4 years
  • 5 years
  • 2 years
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The Correct Option is B

Approach Solution - 1

Step 1: Let Beena's age at marriage be \( M \) years. Since she got married 8 years ago, her present age is \( M+8 \).

Step 2: Her present age is a simple multiple of her age at marriage, in the ratio \( 5:4 \), so \( M+8=\frac{5}{4}M \). This gives \( 8=\frac{1}{4}M \), so \( M=32 \).

Step 3: Her present age is then \( 32+8=40 \) years.

Step 4: Her daughter's age is one-tenth of her present age, so the daughter's age is \( \frac{40}{10}=4 \) years.
\[ \boxed{4 \text{ years}} \]
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Approach Solution -2

Since Beena's present age is \( \tfrac{5}{4} \) times, that is 25 percent more than, her age at marriage, her marriage age can also be seen as her present age divided by 1.25. The eight-year gap between marriage and today must then equal exactly a quarter of her marriage age. We can test each option using this percentage-growth check.

  1. 3 years: Present age \( =30 \). A quarter of this, \( 30 \div 4=7.5 \), should equal the 8-year gap between marriage and today, but it does not.
  2. 4 years: Present age \( =40 \). A quarter of this is \( 40 \div 4=10 \)... checking directly instead via the marriage age: marriage age \( =40 \div 1.25=32 \), and \( 40-32=8 \), matching the 8-year gap exactly.
  3. 5 years: Present age \( =50 \), marriage age \( =50 \div 1.25=40 \), and \( 50-40=10 \), not the required 8 years.
  4. 2 years: Present age \( =20 \), marriage age \( =20 \div 1.25=16 \), and \( 20-16=4 \), not the required 8 years.

Only a daughter's age of 4 years produces a present age that is exactly 8 years, a quarter of the marriage age, ahead of her age at marriage.

Therefore, the correct answer is 4 years.

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