Question

At \(300\,\mathrm{K}\), the diffusion rate of one mole of an ideal gas is \(0.082\,\mathrm{L\,s^{-1}}\). What is the pressure (in atm) of this gas which can diffuse in \(100\,\mathrm{s}\)? \[ \left(R=0.082\,\mathrm{L\,atm\,mol^{-1}\,K^{-1}}\right) \]

• A. \(1\)
• B. \(3\)
• C. \(5\)
• D. \(2\)

Hint:

For one mole of an ideal gas, \[ \boxed{ PV=RT. } \] Always calculate the volume first, then substitute into the ideal gas equation.

Answer 1

The Correct Option is B