Question:medium

At $300\,\mathrm{K}$, a certain reaction has an equilibrium constant equal to 10. The value of $\Delta G^\circ$ for this reaction (in $\mathrm{kJ\,mol^{-1}}$) is:} \[ (R=8.314\,\mathrm{J\,K^{-1}mol^{-1}}) \]

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Remember: \[ \Delta G^\circ=-RT\ln K. \] If $K>1$, then $\Delta G^\circ$ is negative.
Updated On: Jun 17, 2026
  • $-5.74$
  • $+5.74$
  • $-2.49$
  • $+2.49$
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The Correct Option is A

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