Question:medium

Given below are two statements: one is labelled as Assertion $A$ and the other is labelled as Reason $R$
Assertion (A): The nuclear density of nuclides ${ }_5^{10} B ,{ }_3^6 Li ,{ }_{26}^{56} Fe ,{ }_{10}^{20} Ne$ and ${ }_{83}^{209} Bi$ can be arranged as $\rho_{ Bi }^N>\rho_{ Fe }^N>\rho_{ Ne }^N>\rho_{ B }^N>\rho_{ Li }^N$.
Reason R: The radius $R$ of nucleus is related to its mass number $A$ as $R=R_0 A^{1 / 3}$, where $R_0$ is a constant.
In the light of the above statements, choose the correct answer from the options given below

Updated On: Mar 30, 2026
  • Both $A$ and $R$ are true and $R$ is the correct explanation of $A$
  • $A$ is false but $R$ is true
  • Both $A$ and $R$ are true but $R$ is NOT the correct explanation of $A$
  • A is true but $R$ is false
Show Solution

The Correct Option is B

Solution and Explanation

The question requires us to evaluate the correctness of the assertion and reason given, as well as determine the correct relationship between different nuclides' nuclear densities. 

  1. Understanding the Assertion ($A$): The assertion claims that the nuclear densities of the nuclides ${}_5^{10} B$, ${}_3^6 Li$, ${}_{26}^{56} Fe$, ${}_{10}^{20} Ne$, and ${}_{83}^{209} Bi$ can be arranged in the order: \(\rho_{Bi}^N > \rho_{Fe}^N > \rho_{Ne}^N > \rho_{B}^N > \rho_{Li}^N\).
  2. Nuclear Density: The nuclear density is given by \(\rho^N = \frac{m}{V}\), where \(m\) is the mass and \(V\) is the volume of the nucleus. For a nucleus, the volume is proportional to \(R^3\), where \(R\) is the radius defined by the formula:
    • \(R = R_0 A^{1/3}\)
      • \(A\) is the mass number.
      • \(R_0\) is a constant.
  3. The formula implies that nuclear density \(\rho^N\) is approximately constant for most nuclei, as both \(m\) and \(V\) are functions of the mass number \(A\) which cancel each other out (assuming the strong nuclear force gives rise to a roughly constant nuclear density regardless of the nucleus size).
  4. Evaluating the Assertion ($A$): Since the nuclear density is roughly constant across nuclei, the nuclear densities can't be distinctly ranked like normal densities can. Therefore, the assertion $A$ is false.
  5. Understanding the Reason ($R$): The radius \(R\) of a nucleus is indeed related to its mass number \(A\) by the formula \(R = R_0 A^{1/3}\). Thus, the reason $R$ is true and is a well-known equation in nuclear physics.
  6. Conclusion: Option "$A$ is false but $R$ is true" is the correct choice. Although the reason is accurate, it doesn't explain why the assertion is wrong.
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