To solve the given question, we need to analyze both the Assertion (A) and the Reason (R) independently, and then decide how they relate to each other.
Fluorine forms one oxoacid.
Fluorine forms only one oxoacid, which is hypofluorous acid (HOF). This is due to fluorine's high electronegativity and small size, which prevents the formation of multiple oxoacids. Hence, the assertion is correct.
Fluorine has the smallest size amongst all halogens and is highly electronegative.
Fluorine indeed has the smallest atomic size among all halogens. It is also the most electronegative element in the periodic table. These properties result in fluorine's unique chemistry, including its ability to form just one oxoacid, HOF. Therefore, the reason is correct.
Based on the analysis, the most appropriate answer is:
CH$_3$–Br $\xrightarrow{\text{CH$_3$OH/Nu}}$ CH$_3$OH
Correct order of rate of this reaction for given nucleophile:
Match the LIST-I with LIST-II: 
Choose the correct answer from the options given below:

