Question

Ankita walks from A to C through B, and runs back through the same route at a speed that is 40% more than her walking speed. She takes exactly 3 hours 30 minutes to walk from B to C as well as to run from B to A. The total time, in minutes, she would take to walk from A to B and run from B to C, is

Hint:

When speed changes by a fixed percentage, keep everything in terms of one speed (like \(w\)), express all distances using that speed and given times, then recompute the required times with the new speed.

Answer 1

Correct Answer: 444

Step 1: Let walking speed \( = w \), so running speed \( = 1.4w \). Walking B to C: distance \( BC = 210w \). Running B to A: distance \( AB = 210 \times 1.4w = 294w \).
Step 2: Time to walk A to B \( = \frac{294w}{w} = 294 \) minutes.
Step 3: Time to run B to C \( = \frac{210w}{1.4w} = 150 \) minutes.
Step 4: Total time \( = 294 + 150 = 444 \) minutes.
\[ \boxed{444 \text{ minutes}} \]