An organic compound contains C, H and S. The minimum molecular weight of the compound containing 8% sulphur is : (atomic weight of S=32 amu)

Question

In the reaction, \[ 2\text{Al}(s) + 6\text{HCl}(aq) \rightarrow 2\text{Al}^{3+}(aq) + 6\text{Cl}^-(aq) + 3\text{H}_2(g) \]

Answer 1

To find the minimum molecular weight of the compound containing 8% sulfur, we start by using the percentage composition formula:

\text{Percentage of Sulfur} = \frac{\text{Atomic weight of S} \times \text{Number of S atoms}}{\text{Molecular weight}} \times 100

Given that the percentage of sulfur is 8%, and the atomic weight of sulfur is 32 amu, we set up the equation:

8 = \frac{32 \times 1}{\text{Molecular weight}} \times 100

Simplifying the equation:

\frac{32}{\text{Molecular weight}} \times 100 = 8

Rearranging to solve for the molecular weight:

\text{Molecular weight} = \frac{32 \times 100}{8}

Calculating the molecular weight:

\text{Molecular weight} = 400\, \text{g mol}^{-1}

Thus, the minimum molecular weight of the compound that contains 8% sulfur is 400\, \text{g mol}^{-1}.

Therefore, the correct answer is {400\, g \, mol^{-1}}.

Answer 2