An LC circuit with negligible resistance containing a 20 mH inductor and a 50 \(\mu F\) capacitor with an initial charge of 10 mC is closed at \(t=0\). Then the minimum time taken (in \(\mu s\)) for the total energy to be shared equally between the inductor and capacitor is:
Show Hint
In an LC circuit, equal energy sharing first occurs at
\[
t=\frac{T}{8}
=
\frac{\pi}{4\omega}.
\]