Question:medium

An LC circuit with negligible resistance containing a 20 mH inductor and a 50 \(\mu F\) capacitor with an initial charge of 10 mC is closed at \(t=0\). Then the minimum time taken (in \(\mu s\)) for the total energy to be shared equally between the inductor and capacitor is:

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In an LC circuit, equal energy sharing first occurs at \[ t=\frac{T}{8} = \frac{\pi}{4\omega}. \]
Updated On: Jun 18, 2026
  • \(375\pi\)
  • \(125\pi\)
  • \(500\pi\)
  • \(250\pi\)
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The Correct Option is D

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