Question:medium
An instantaneous displacement of a simple harmonic oscillator is \( x = A \cos(\omega t + \pi/4) \). Its speed will be maximum at time
An instantaneous displacement of a simple harmonic oscillator is \( x = A \cos(\omega t + \pi/4) \). Its speed will be maximum at time
Show Hint
In simple harmonic motion, the speed is maximum when the sine function reaches its peak value of 1.
Updated On: Mar 24, 2026
- \( \frac{\pi}{4 \omega} \)
- \( \frac{\pi}{2 \omega} \)
- \( \frac{\pi}{\omega} \)
- \( \frac{2 \pi}{\omega} \)
Show Solution
The Correct Option is A
Solution and Explanation
Was this answer helpful?
0
Top Questions on Energy in simple harmonic motion
- A ring and a solid sphere are released from rest from the same height on enough rough inclined surface. The ratio of their speed when they reach the bottom is \( \sqrt{\frac{7}{x}} \) m/s, then \( x \) is ______.
- JEE Main - 2025
- Physics
- Energy in simple harmonic motion
- In a simple pendulum of length 10 m, the string is initially kept horizontal and the bob is released. 10% of energy is lost till the bob reaches the lowest position. Then find the speed of the bob at the lowest position.
- JEE Main - 2024
- Physics
- Energy in simple harmonic motion
A bullet of mass \(10^{-2}\) kg and velocity \(200\) m/s gets embedded inside the bob of mass \(1\) kg of a simple pendulum. The maximum height that the system rises by is_____ cm.
- JEE Main - 2024
- Physics
- Energy in simple harmonic motion
- The length of a seconds pendulum if it is placed at height \(2R\) from the surface of the earth (R: radius of earth) is \(\frac{10}{xπ^2}\) \(m\). Find \(x\)
- JEE Main - 2024
- Physics
- Energy in simple harmonic motion
- Want to practice more? Try solving extra ecology questions todayView All Questions