List of top Physics Questions on Energy in simple harmonic motion asked in BITSAT

The displacement of a particle is given at time t, by: x = Asin(-2ω t) + Bsin² ω t Then,
A particle of mass m executes SHM with amplitude a and frequency ν. The average kinetic energy during its motion from the position of equilibrium to the end is:
A point particle of mass 0.1kg is executing S.H.M. of amplitude 0.1m. When the particle passes through the mean position, its kinetic energy is 8×10⁻3J. Obtain the equation of motion of this particle if its initial phase of oscillation is \(45^\circ\).
Two particles P and Q describe S.H.M. of same amplitude and same frequency along the same straight line. The maximum distance between the two particles is \(2A\). The initial phase difference between the particles is:
A tunnel is dug through the centre of the earth and a ball is released in it. It executes S.H.M. with time period:
An instantaneous displacement of a simple harmonic oscillator is \( x = A \cos(\omega t + \pi/4) \). Its speed will be maximum at time