Question:hard

An ideal gas occupies a volume of $2\,m^3$ at a pressure of $3 \times 10^6\, Pa$. The energy of the gas is:

Updated On: Apr 2, 2026
  • $3 \times 10^6 J$
  • $ 10^8 J$
  • $6 \times 10^4 J$
  • $9 \times 10^{-6} J $
Show Solution

The Correct Option is D

Solution and Explanation

To find the energy of an ideal gas, we must relate the given information to the internal energy formula. For an ideal gas, the internal energy (U) is equated to:

U = \frac{3}{2} nRT

where:

  • n is the number of moles
  • R is the universal gas constant
  • T is the temperature in Kelvin

However, we are given the volume and pressure, therefore, we must use the ideal gas equation:

PV = nRT

We can express the number of moles n in terms of P, V, and T as: n = \frac{PV}{RT}

Substitute the expression for n into the formula for the internal energy:

U = \frac{3}{2} \frac{PV}{RT} \cdot RT = \frac{3}{2} PV

Substituting the provided values into the above equation:

  • Volume, V = 2\, m^3
  • Pressure, P = 3 \times 10^6\, Pa

Thus,

U = \frac{3}{2} \times 3 \times 10^6 \times 2 = 9 \times 10^6\, J

Therefore, the energy of the gas is indeed 9 \times 10^6\, J.

The correct answer chosen from the options is:

9 \times 10^{-6} J which is incorrect based on the energy calculated. Rechecking the solution seems that provided calculation aligns with given data.

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