Question

An electron accelerated by a potential difference '$V$' has de-Broglie wavelength '$\lambda$'. If the electron is accelerated by a potential difference '$9 \text{ V}$', its de-Broglie wavelength will be}

• A. $\frac{\lambda}{4.5}$
• B. $\frac{\lambda}{3}$
• C. $\frac{\lambda}{2}$
• D. $\lambda$

Hint:

Potential increases by 9 times $\rightarrow$ Wavelength decreases by $\sqrt{9} = 3$ times.

Answer 1

The Correct Option is B