List of top Physics Questions on de broglie hypothesis asked in MHT CET

Find the ratio of the de Broglie wavelengths of a proton and an alpha particle accelerated through the same potential difference.
Calculate the de-Broglie wavelength of an electron accelerated through a potential difference of \(100\text{ V}\).
An electron of mass 'm' and charge 'e' initially at rest gets accelerated by a constant electric field 'E'. The rate of change of de-Broglie wavelength of the electron at time 't' is (Ignore relativistic effect) ($h$ = Planck's constant) ______.
The wavelength '$\lambda$' of a photon and the deBroglie wavelength of an electron have same value. The ratio of kinetic energy of the electron to the energy of a photon is ______.
Let $E_{e}$ and $E_{p}$ represent kinetic energy of electron and photon. If de-Broglie wavelength of photon is twice that of electron, find $E_p/E_e$ (speed of electron $= c/100$)}
An electron accelerated by a potential difference '$V$' has de-Broglie wavelength '$\lambda$'. If the electron is accelerated by a potential difference '$9 \text{ V}$', its de-Broglie wavelength will be}
An electron accelerated by a potential difference '$V$' has de-Broglie wavelength '$\lambda$'. If the electron is accelerated by a potential difference '$9 \text{ V}$', its de-Broglie wavelength will be}
A photon and an electron have the same energy \( E \). If \( \lambda_p \) is the wavelength of the photon and \( \lambda_e \) is the de Broglie wavelength of the electron, then the ratio \( \frac{\lambda_p}{\lambda_e} \) is:
A photon and an electron have the same energy \( E \). If \( \lambda_p \) is the wavelength of the photon and \( \lambda_e \) is the de Broglie wavelength of the electron, then the ratio \( \frac{\lambda_p}{\lambda_e} \) is:
According to de-Broglie hypothesis if an electron of mass '$m$' is accelerated by potential difference '$V$', the associated wavelength is '$\lambda$'. When a proton of mass '$M$' is accelerated through potential difference $9V$, then the wavelength associated with it is
When an electron in hydrogen atom jumps from third excited state to the ground state, the de-Broglie wavelength associated with the electron becomes
A proton and alpha particle are accelerated through the same potential difference. The ratio of the de-Broglie wavelength of proton to that of alpha particle will be (mass of alpha particle is four times mass of proton.)