The ratio of the kinetic energy of the artillery to that of the shell is calculated using the principles of conservation of momentum and the definition of kinetic energy.
- Conservation of Momentum: \(M_1 \cdot V_1 = M_2 \cdot V_2\) This equation represents the conservation of momentum, where \( M_1 \) and \( M_2 \) are the masses of the artillery and shell, and \( V_1 \) and \( V_2 \) are their respective velocities after firing.
- Kinetic Energy Formula: The kinetic energy (KE) of an object is defined as: \(\frac{1}{2}mv^2\) where \( m \) is the object's mass and \( v \) is its velocity.
- From the conservation of momentum equation, the artillery's velocity can be expressed as: \(V_1 = \frac{M_2 \cdot V_2}{M_1}\)
- Kinetic Energy of Artillery: The kinetic energy of the artillery is: \(K.E._{artillery} = \frac{1}{2}M_1V_1^2 = \frac{1}{2}M_1 \left(\frac{M_2 \cdot V_2}{M_1}\right)^2 = \frac{1}{2} \frac{M_2^2 \cdot V_2^2}{M_1}\)
- Kinetic Energy of Shell: The kinetic energy of the shell is: \(K.E._{shell} = \frac{1}{2}M_2V_2^2\)
- Ratio of Kinetic Energies: The ratio of the artillery's kinetic energy to the shell's kinetic energy is computed as: \(\text{Ratio} = \frac{\frac{1}{2} \frac{M_2^2 \cdot V_2^2}{M_1}}{\frac{1}{2}M_2 \cdot V_2^2} = \frac{M_2}{M_1}\)
- Conclusion: Therefore, the ratio of the kinetic energy of the artillery to that of the shell is \(\frac{M_2}{M_1}\).
This derivation utilizes the physical principles of momentum conservation and kinetic energy definition to arrive at the final ratio.