To determine the pressure differential within the bubble, it is essential to first identify the contributing pressures. An air bubble submerged in a liquid is subjected to hydrostatic pressure, resulting from the liquid column above, and pressure due to surface tension.
1. Hydrostatic Pressure Calculation:
Hydrostatic pressure \(P_{\text{hydro}}\) at a depth \(h\) is calculated as:
\(P_{\text{hydro}} = \rho \cdot g \cdot h\)
where:
\(\rho = 1000 \, \text{kg/m}^3\) (liquid density),
\(g = 10 \, \text{m/s}^2\) (gravitational acceleration),
\(h = 0.2 \, \text{m}\) (depth).
Therefore:
\(P_{\text{hydro}} = 1000 \cdot 10 \cdot 0.2 = 2000 \, \text{Pa}\).
2. Surface Tension Pressure Calculation:
The pressure within a bubble attributed to surface tension, \(P_{\text{surface}}\), is given by:
\(P_{\text{surface}} = \frac{2 \cdot T}{r}\)
where:
\(T = 0.095 \, \text{J/m}^2\) (surface tension),
\(r = 0.001 \, \text{m}\) (bubble radius).
Thus:
\(P_{\text{surface}} = \frac{2 \cdot 0.095}{0.001} = 190 \, \text{Pa}\).
3. Total Internal Bubble Pressure Calculation:
The total pressure within the bubble, \(P_{\text{inside}}\), is:
\(P_{\text{inside}} = P_{\text{atmospheric}} + P_{\text{hydro}} + P_{\text{surface}}\)
To ascertain the pressure difference relative to atmospheric pressure, \(P_{\text{atmospheric}}\) is omitted from the calculation of the difference:
The resultant pressure difference is:
\(P_{\text{diff}} = P_{\text{hydro}} + P_{\text{surface}} = 2000 + 190 = 2190 \, \text{Pa}\).
The discrepancy between the internal bubble pressure and atmospheric pressure is determined to be 2190 Pa. This precise calculation accurately reflects the provided data and confirms the solution.
Consider a water tank shown in the figure. It has one wall at \(x = L\) and can be taken to be very wide in the z direction. When filled with a liquid of surface tension \(S\) and density \( \rho \), the liquid surface makes angle \( \theta_0 \) (\( \theta_0 < < 1 \)) with the x-axis at \(x = L\). If \(y(x)\) is the height of the surface then the equation for \(y(x)\) is: (take \(g\) as the acceleration due to gravity) 